Basic Chemical Stoichiometric Material
Understanding Stoichiometry
Stoichiometry comes from two Greek syllables Stoicheion meaning "element" and Metron which means "measurement".
Stoichiometry is a subject in chemistry involving the linkage of reactants and products in a chemical reaction to determine the quantity of each reacting agent.
More easily,
"Stoichiometry is a subject in chemistry that studies the quantity of matter in a chemical reaction."
If there is a chemical reaction, you may want to know how many substances the reaction results? Or if you want to do a chemical reaction to produce a certain amount of product, then you have to adjust how many reactants in the reaction. These are all discussed in stoichiometry.
Stoichiometry comes from two Greek syllables Stoicheion meaning "element" and Metron which means "measurement".
Stoichiometry is a subject in chemistry involving the linkage of reactants and products in a chemical reaction to determine the quantity of each reacting agent.
More easily,
"Stoichiometry is a subject in chemistry that studies the quantity of matter in a chemical reaction."
If there is a chemical reaction, you may want to know how many substances the reaction results? Or if you want to do a chemical reaction to produce a certain amount of product, then you have to adjust how many reactants in the reaction. These are all discussed in stoichiometry.
Before doing Stoichiometric calculations, the equation of the reaction we have must be equalized first. Before doing the calculation of Stoichiometry, the equation of the reaction we have must be equalized first.
Equalization of Chemical Reaction
Chemical reactions are often written in bentu equations using element symbols. The reactants are the substances that are on the left, and the product is the substance that is on the right, then both are separated by arrows (can be one or two alternating arrows). Example:
2Na(s)+HCl(aq)→2NaCl(aq)+H2(g)
The equation of a chemical reaction is like a prescription in the reaction, thus indicating everything associated with the reaction, whether it is an ion, an element, a compound, a reactant or a product. All.
Then as in the recipe, there is a proportion of the equation shown in the figures in front of the molecular formula.
When considered again, the number of H atoms on the reactant (left) is not equal to the number of H atoms on the product (right). Then this reaction needs to be synchronized. The equalization of chemical reactions must satisfy some chemical laws of matter.
The Law of Conservation of Mass
Mass Losing Law: The mass of the product is equal to the mass of the reactants
Fixed Comparative Law (Proust Law)
Fixed Comparison Law: The chemical compound consists of chemical elements with the ratio of the mass of elements that remain the same.
The Law of Multiple Comparisons (Dalton's Law)
The Law of Multiple Comparisons: If an element reacts with other elements, then the ratio of the weight of the element is a simple integer
So from the equation:
2Na(s)+2HCl(aq)→2NaCl(aq)+H2(g)
We can know that 2 moles of HCl react with 2 moles of Na to form 2 moles of NaCl and 1 mole of H2. By equalizing this reaction, it can be known the quantity of each substance involved in the reaction.
Hence the equalization of this reaction is very important in solving stoichiometric problems.
Example:
Lead (IV) Hydroxide reacts with Sulfuric Acid, by reaction as follows:
Pb(OH)4+H2SO4→Pb(SO4)2+H2O
If we look good either:
Unsur
|
Reaktan
(jumlah mol) |
Product
(jumlah mol) |
Pb
|
1
|
1
|
O
|
8
|
9
|
H
|
6
|
2
|
S
|
1
|
2
|
Then this equation is not equivalent. Therefore we need to equate this equation. In the reactant there are 16 atoms, but on its products there are only 14 atoms. This equation needs to add coefficients so that the number of atoms of the elements is the same.
In front of H2SO4 it is necessary to add coefficient 2 so that the number of sulfur atoms corresponds, then in front of H2O it is necessary to add coefficient 4 so that the number of oxygen atoms is appropriate. Then the equivalent reaction is:
Pb(OH)4+2H2SO4→Pb(SO4)2+4H2O
Unsur
|
Reaktan
(jumlah mol) |
Product
(jumlah mol) |
Pb
|
1
|
1
|
O
|
12
|
12
|
H
|
8
|
8
|
S
|
2
|
2
|
The condition in which the equation of the reaction is equal is when it satisfies the following two criteria:
1.The number of atoms of each element on the left and right sides of the equation has been the same.
2.The number of ions on the left and right has been the same (using redox reaction equation)
Stoichiometric Calculations on Equivalent Chemical Equations
In stoichiometry, an equivalent chemical equation provides information to compare each element in a reaction based on a stoichiometric factor. The stoichiometric factor is the ratio of the moles of each reacting substance / substance.
In real life, this is an example:
To make a delicious cup of coffee, a recipe is required that is 9 cube sugar with 3 tablespoons of coffee.
Stoichiometric illustration in Life
This is a fix and patent recipe. So what if we have 12 sugar cubes and three spoons of coffee powder, how many cups of coffee can be made?
Yes! The answer is 1 cup of coffee, with the remaining ingredients 3 sugar.
How about we have 27 sugars and 8 spoons of coffee. How many cups of coffee can be made?
Of course 2 cups of coffee with the remaining 9 sugar and 2 coffee spoons. All absolutely must follow the recipe.
The key is that all must follow the prescription, if in stoichiometry, the equivalent reaction equation is the recipe, so we must follow the recipe.
Understanding Molar Mass
Before performing stoichiometric calculations, we need to know what a molar mass is. The molar mass is the ratio between the mass and moles of an atom.
To know the Molar Mass of an element then we only need to read it in the periodic table of elements. As for knowing the Molar Mass compound we need to calculate it based on the molecular formula of the compound.
zura, try to give an example about stoichiometry?
BalasHapusPropane burns by reaction equation:
HapusC3H8+O2→H2O+CO2
If 200 g of propane is burned, then how much H2O is formed?
Answer:
First: Resolve the equation of the reaction!
C3H8+5O2→4H2O+3CO2
Second: Calculate mol C3H8 !
mol=m/Mr -> mol= 200 g/ 44 g/mol ->mol= 4.54 mol
Third: Calculate the ratio of H2O : C3H8 -> 4:1 (* based on the comparison coefficient on the equation of the reaction)
Fourth: Calculate the mole of H2O by comparison
mol H2O : 4 = mol C3H8 : 1
-> mol H2O : 4 = 4.54 mol : 1
-> mol H2O = 4.54 x 4= 18.18 mol
Fifth: Convert from mol to gram.
mol= m/Mr -> m= mol x Mr -> m= 18.18 mol x 18 = 327.27 gram.
What is the molar mass of H2O?
BalasHapus2 (1.00794g / mol) + 1 (15.9994g / mol) = 18.01528g / mol
HapusThe molar mass of Hydrogen is 1.00794g / mol multiplied by 2 because there are two hydrogen atoms in one water compound. Then the molar mass of oxygen is added.
Please explain the laws that govern the stoichiometry!
BalasHapusStoichiometry rests on laws such as fixed comparison law, double comparative law and law and conservation of mass.
HapusThe law of conservation of mass: Using the laws of physics like the law of conservation of mass, which states that the mass of the reactants is equal to the mass of the product, Stoichiometry is used to gather information about the amount of various elements used in chemical reactions, and whether they take the form of gas, solid or liquid.
The comparative law remains: It states that a chemical compound (substance consisting of 2 or more ages) always contains the same proportion of elements (compounds with one atom type) with mass.
Stoichiometry
Law of multiple comparisons: This is one of the basic laws of stoichiometry, besides the law of fixed comparison. Sometimes referred to as Dalton's law. It is said that, if 2 elements form more than 1 compound between them, then the mass ratio of the second element joining the fixed mass of the first element will both have a ratio of a small sum of the whole.
Give examples of mass comparison law ?
BalasHapusThe law of conservation of the masses
HapusMass before reacting = mass after reacting
What makes reactants in each element different?
BalasHapusBecause it has different electron configuration different
HapusHow to determine the reaction, is it acid oralkaline?
BalasHapusBy means of acid-base titration
HapusPlease give me the example of proust law
BalasHapus1. LAW MASS LAW = LAVOISIER LAW
Hapus"The mass of substances before and after the reaction is fixed".
Example:
Hydrogen + Oxygen ® Hydrogen Oxide
(4g) (32g) (36g)
2. PERSONAL COMPARATIVE LAW = PROUST LEGAL
"The ratio of the mass of the elements in each compound is fixed"
Example:
A. In the compound NH3 = mass N: mass H
= 1 Ar. N: 3 Ar. H
= 1 (14): 3 (1)
= 14: 3
B. On the SO3 compound = mass S: mass 0
= 1 Ar. S: 3 Ar. O
= 1 (32): 3 (16)
= 2: 3
Advantages of Proust Law:
If known mass of a compound or mass of one element that make up the compound make the mass of other elements can be known.
Example:
What is the level of C in 50 grams CaCO3? (Ar: C = 12; 0 = 16; Ca = 40) ????
Mass C = (Ar C / Mr CaCO3) x CaCO3 mass
= 12/100 x 50 grams = 6 grams
Levels C = mass C / CaCO3 mass x 100%
= 6/50 x 100% = 12%
3. COMPARATIVE LAWS = LEGAL DALTON
"If two elements can form two or more compounds for the mass of one element equal to the number then the ratio of the mass of the second element will be proportional to the integer and the simple".
Example:
When the elements of Nitrogen and oxygen are compounded to form,
NO where the mass N: O = 14: 16 = 7: 8
NO2 where the mass N: O = 14: 32 = 7: 16
For the same mass of Nitrogen the Oxygen mass ratio of NO: NO2 = 8: 16 = 1: 2
4. GAS LAW
For ideal gas apply equation: PV = nRT
Where:
P = gas pressure (atmosphere)
V = volume of gas (liter)
N = mol of gas
R = universal gas constant = 0.082 lt.atm / mol Kelvin
T = absolute temperature (Kelvin)
Give an example of the problem along with the steps of equalizing the reaction
BalasHapusSteps or equivalence stages are as follows:
Hapus1. Divide the reaction into 2 parts half-reaction, collect the species that have atomic similarity (except O and H need not be considered). It is permissible to add the same substance to two half-part reactions if necessary;
2. Equalize the number of atoms other than atoms O and H;
3. Equalize the number of O atoms by adding OH- to the deficient side O in any ambience, and equalize the number of H atoms by adding H + to the H-deficient side;
4. Equating the amount of charge by adding e-;
5. If necessary multiply every half-reaction with an integer so that the electron removed is the same as the one received. Remember the redox reaction of the electron-transferring reaction.
6. Add the two half-reactions, and write the remaining margin if found the same species on the left and right sides;
7. Adding H + or OH- (according to the requested atmosphere) on the left and right if necessary;
8. If on one segment there are H + ions and also OH - then necessary
Convert it to H2O molecule;
9 Ensure the number of atoms and cargo is equal.
why we must learning stoichiometry?
BalasHapusWhy should we study stoichiometry? One reason, because studying chemistry can not be separated from doing experiments in the laboratory. Sometimes in our laboratory we have to react a number of grams of substance A to produce a number of grams of substance B. The question that often arises is if we have a number of grams of substance A, how many grams of substance B will be generated? To answer that question we need stoichiometry.
HapusPlease give an example of redox reaction equation.
BalasHapusFe2+(aq) + Cr2O72-(aq) ——> Fe3+(aq) + Cr3+(aq)
Hapus1. Write down the overall reaction equation
Fe2++ Cr2O72- ——> Fe3++ Cr3+
2. Divide the reaction into two half reactions
Fe2+ ——> Fe3+
Cr2O72- ——> Cr3+
3. Equalizes the type of atom and the number of atoms and charge in each half-reaction; In an acidic atmosphere, add H2O to equal the atoms O and H + to equalize the H atom
Fe2+ ——> Fe3++ e–
6 e– + 14 H+ + Cr2O72- ——> 2 Cr3+ + 7 H2O
4. Sums up the two half-reactions; Electrons on both sides must eliminate each other; If oxidation and reduction have different number of electrons, it must be equated first
6 Fe2+ ——> 6 Fe3+ + 6 e– ……………… (1)
6 e– + 14 H+ + Cr2O72- ——> 2 Cr3+ + 7 H2O ……………… (2)
6 Fe2+ + 14 H+ + Cr2O72- ——> 6 Fe3+ + 2 Cr3+ + 7 H2O ………………… [(1) + (2)]
5. Checking again and convinced that the two sides have the same type of atom and number of atoms, and have the same charge on both sides of the equation
For reactions that take place in an alkaline atmosphere, add the OH ions - in an amount equal to the H + ions in each segment to remove the H + ions. The equation of the reaction turns into the following:
6 Fe2+ + 14 H+ + 14 OH– + Cr2O72- ——> 6 Fe3+ + 2 Cr3+ + 7 H2O + 14 OH–
6 Fe2+ + 14 H2O + Cr2O72- ——> 6 Fe3+ + 2 Cr3+ + 7 H2O + 14 OH–
6 Fe2+ + 7 H2O + Cr2O72- ——> 6 Fe3+ + 2 Cr3+ + 14 OH–
What factors affect stoichiometry?
BalasHapusRelative Atomic Mass
HapusMaterial Quantity and Mol
The atomic mass unit (sma)